Easy String

Author: sharmasapna

242.py

@@ -0,0 +1,27 @@
+#242
+from collections import defaultdict,Counter
+class Solution:
+    def isAnagram(self, s: str, t: str) -> bool:
+## Comparing the sorted strings
+        return sorted(s) == sorted(t)
+## Comparing two hash maps
+        return Counter(s) == Counter(t)
+        
+## intutive solution         
+        dic = {}
+        
+        for a in s:
+            if a in dic:
+                dic[a] += 1
+            else:
+                dic[a] = 1
+        for b in t:
+            if b in dic:
+                dic[b] -= 1
+            else:
+                dic[b] = -1
+        #print(max(dic.values()))
+        if max(dic.values()) == 0 and min(dic.values()) == 0:
+            return True
+## for video pl watch : https://www.youtube.com/watch?v=9UtInBqnCgA
+