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刘军
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doc/ms/ms.md

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Return 4.
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#### 2、动态规划:
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#### 动态规划:
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递推公式:dp[i][j] = min(dp[i][j-1], dp[i-1][j], dp[i-1][j-1]) + 1
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```
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讲解:
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#### 讲解:
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我们用 dp(i, j) 表示以 (i, j) 为右下角,且只包含 1 的正方形的边长最大值。
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