checkered-board.md

Checkered Board ^{6 Kyu}

^{LINK TO THE KATA - STRINGS ASCII ART FUNDAMENTALS}

Description

Write a function which takes one parameter representing the dimensions of a checkered board. The board will always be square, so 5 means you will need a 5x5 board.

The dark squares will be represented by a unicode white square, while the light squares will be represented by a unicode black square (the opposite colours ensure the board doesn't look reversed on code wars' dark background). It should return a string of the board with a space in between each square and taking into account new lines.

An even number should return a board that begins with a dark square. An odd number should return a board that begins with a light square.

Examples

Input: 5

Output:
■ □ ■ □ ■
□ ■ □ ■ □
■ □ ■ □ ■
□ ■ □ ■ □
■ □ ■ □ ■

There should be no trailing white space at the end of each line, or new line characters at the end of the string.

Note

The squares are characters ■ and □ with codes \u25A0 and \u25A1.
Do not use HTML entities for the squares (e.g. □ for white square) as the code doesn't consider it a valid square. A good way to check is if your solution prints a correct checker board on your local terminal.

Solution

const isEven = number => number % 2 === 0

const checkeredBoard = dimension => {
  let oddRow = []
  let evenRow = []

  for (let i = 0; i < dimension; i++) {
    if (isEven(dimension)) {
      oddRow.push(isEven(i) ? '■' : '□')
      evenRow.push(isEven(i) ? '□' : '■')
    } else {
      oddRow.push(isEven(i) ? '□' : '■')
      evenRow.push(isEven(i) ? '■' : '□')
    }
  }

  oddRow = oddRow.join(' ')
  evenRow = evenRow.join(' ')

  const board = []

  for (let i = 0; i < dimension; i++) {
    board.push(isEven(i) ? evenRow : oddRow)
  }

  return board.join('\n')
}